REMEMBER
TO
BRING AN 8’’x11” BLUE
EXAM BOOKLET FOR THE TEST
KEY CONCEPTS AND MAIN DEFINITIONS:
Ch.1- Ch.7
(CSA) of cones, truncated cones &
sphere; and volume of sphere, Areas of regions
bounded by parabolas & the Archimedean spiral,
Area of the triangle, The Julian and
Gregorian Calendars, leap years, Heron's triangle
formula, Solids formed by revolving
plane regions, Surfaces formed by revolving plane
curves, Centroids of plane regions,
Centroids of plane curves, The two Theorems of
Pappus.
1.
Multiplying two numbers and diving one
numb. by another using the Egyptian method
2. Finding volumes of pyramids & cones, and frustrums
(truncated pyramids & cones)
3. Finding k-th approximation to the square root of a
numb. using the Babylonian method
8. Extracting square-roots digit by
digit by the Theon of Alexandria Algorithm
9. Justifying the formulas for the curved surface areas of
the cone, frustrum, & sphere
10. Justifying the formulas for the volume of the solid frustrum and
the solid sphere.
11. Determining which years are leap years according to the Gregorian
Calendar of 1582.
12. Finding volumes and surface areas by using the two Theorems of
Pappus.
13. Finding the centroids of a plane region R and of a plane curve C.
MAIN FORMULAS:
1. AREABabylon(Circle)
= (3D)2/12
= 3.r2, AREAEgypt(Circle)
= (8D/9)2
= (256/81).r2
2. Vol.(pyramid or cone) =
(h/3).(base B), Vol.(frustrum) = (h/3).[B1 + (B1.B2)1/2
+ B2]
3. A0 = Goodish initial guess, A1
= (A0 + n/A0)/2, . . . ., Ak+1
= (Ak + n/Ak)/2
4. If a = u2 - v2, b = 2uv, c = u2
+ v2; then <a,b,c> &
<b,a,c> are Pythagorean triples
5. Amean(a,b) = (a+b) / 2, Gmean(a,b) = (a.b)1/2, Hmean(a,b) = (2.a.b) / (a+b)
6. AC2 = AB2 + BC2
(Pythagoras), AC2 = AB2 + BC2
- 2.BC.BD (Euclid)
7. AREAArchim (Circle) = r.(C/2), C =
2.(Pi).r,
223/71 < Pi < 220/70 = 22/7
11. Heron's formula: Area (triangle)
= [s(s-a)(s-b)(s-c)]1/2 where s =
(a+b+c)/2
12. Vol.(Solid of revol.) = (area of
region). (length of the path the centroid traces out)
13. Area(Surface of revol.) = (length of
curve).(length of the path the centroid traces out)
14. xc(R) = Inta to b[x.(y2-y1)dx]
/ Area(R),
yc(R) = Inta to b[y.(x2-x1)dy]
/ Area(R),
15. xc(C) =
Int[x.{1+(y')2}1/2dx]
/ Length(C), yc(C) = Int[y.{1+(x')2}1/2dy]
/ Length(C)