Even Homework Answers

 Section 1.2

16a)

19, 22, 37, 3n + 1

 

16c)

32, 64, 2048,

 

16d)

 

18) 15 paths

22a) 19, 31, 50

22b) 6, 13, 33

22c) 8, 11, 30

26) 19 squares, 2n – 1

 

Section 2.2

16a)

 

 

 

 

 

 

Section 2.3

Section 3.1

4a) P = 33.05 in.
4b) 28.8 cm.
10a) d = 12 ft., r = 6 ft.
10b) d = 5.05 cm, r = 2.53 cm.
28) A = 20 sq. in. The area of the unshaded region is one-half the area of the total region.

Section 3.2

38) 1256 sq. ft.

Section 3.3

4a) 180m2

4b)

30) The sum of the areas of the 3 triangles equals the area of the trapezoid:

Multiplying both sides by 2 to get rid of the fractions:

ab + ab + c2 = (a + b)(a + b)

2ab + c2 = a2 + 2ab + b2

Subtracting 2ab from both sides:

c2 = a2 + b2

 

 Section 3.5

28a) volume of A = 125,000 cubic cm., volume of B = 125,000 cubic cm., volume of C = 125,000 cubic cm.

28b) surface area of A = 15,000 sq. cm., surface area of B = 17,500 sq. cm., surface area of C = 19,500 sq. cm.
28c) No
28d) Box A
52) 3.77 gallons

Section 4.1

18) True. The converse says: "If an angle is obtuse, then it measures 117 degrees. False.
26) False. The converse says: "If two angles are adjacent, then they share a common vertex." True.

Section 4.2

10) Not necessarily congruent (no AAA Congruence Postulate)
14) Not necessarily congruent (triangle HIL has SSA, not ASA)
22) D
24) CBA, ASA Congruence Postulate
26) C, CPCTC (Corresponding Parts of Congruent Triangles are Congruent)
35) Note that the segments in steps 2 and 3 should have segments signs over them.

StatementsReasons
1. ABCD is a rhombus1. Given
2. AB CD, ADCB 2. Definition of a rhombus
3. BDBD 3. Reflexive Property
4. ABDCDB4. SSS Congruence Postulate

37) Note that the segments in steps 1and 2should have segments signs over them.

StatementsReasons
1. Segments AC and BD divide each other in half1. Given
2. AECE, BEDE2. Definition of "divides each other in half"
3. angle BECangle DEA3. Vertical angles are
4. BECDEA4. SAS Congruence Postulate
5. angle DBCangle BDA5. CPCTC
41) Note that the segments in steps 2 and 4 should have segments signs over them.
StatementsReasons
1. ACF and AEB are right triangles1. Given
2. ABAF, BCFE2. Given
3. AB+BC = AF + FE3. Adding = quantities to both sides of the equation
4. ACAE4. Segment Addition
5. ACFAEB5. HL Congruence Theorem
6. angle ACF angle AEB6. CPCTC

46) The ropes are the same length so ADCD . The ropes are anchored the same distance from the base of the tree so ABCB .
Since DBDB , we know ABD CBD by SSS Congruence Postulate. Thus, angle ABD angle CBD by CPCTC. Since angle ABD and angle CBD are also adjacent and supplementary, they both measure 90°. Therefore, the tree will be perpendicular to the ground.

Section 4.3

9.Note that the segments in steps 2 and 5 should have segments signs over them.

StatementsReasons
1. angle WVY angle WXYangle WYVangle XWY1. Given
2. VWWY YX 2. If 2 angles of a triangle are , then the sides opposite those angles are .
3. angle VWYangle XYW3. Each is 180 degrees minus 2 angles
4. WVY YWX 4. SAS Congruence Postulate
5. WXYV5. CPCTC
11. Note that the segments in steps 1and 3 should have segments signs over them.
StatementsReasons
1. PY & RX are altitudes
PXRY
1. Given
2. PXR & RYP are right triangles2. Definition of altitude
3. PRPR3. Reflexive Property
4. PXR RYP 4. HL Congruence Theorem
13. Note that the segments in steps 1, 5, 7, 8 and 9 should have segments signs over them.
StatementsReasons
1. BD is an altitude of ABC
BD is the bisector of angle B
1. Given
2. angle BDA & angle BDC are right angles2. Definition of altitude
3. angle BDA angle BDC3. All right angles are
4. angle ABD angle CBD4. Definition of bisector
5. BD BD 5. Reflexive property
6. ABD CBD 6. ASA Congruence Postulate
7. ADDC7. CPCTC
8. BD is perpendicular to AC8. Definition of altitude
9. BD is the perpendicular bisector of AC9. Definition of perpendicular bisector
15. Note that the segments in steps 1, 2, 3, 7and 8 should have segments signs over them.

Given: ABC is isosceles with ABCB
BD is a median

Prove: BD is the perpendicular bisector of AC

StatementsReasons
1. ABCB
BD is a median
1. Given
2. AD CD, BD bisects AC2. Definition of median
3. BDBD3. Reflexive property
4. ABD CBD 4. SSS Congruence Postulate
5. angle ADB angle CDB5. CPCTC
6. angle ADB & angle CDB are right angles 6. Two angles that are supplementary are right angles.
7. BD is the perpendicular to AC7. Definition of perpendicular
8. BD is the perpendicular bisector of AC8. Definition of perpendicular bisector

22. The worker positioned board CD at the midpoint of board AB, so as long as the
distances AC and BC are equal, the boards are perpendicular by Theorem 4.10.

Section 5.1

2) angles 2 and 5, angles 9 and 12
4) angles 4 and 8, angles 6 and 14
12) angle 20
14) angle 4
32) angle 1 = 47°, angle 2 = 47°, angle 3 = 106°, angle 4 = 133°

Section 6.1

48) Width = 16.2 in., height = 21.6 in.

Section 6.2

26)