Even Homework Answers
16a) 19, 22, 37, 3n + 1 | 16c) 32, 64, 2048, | 16d)
|
18) 15 paths
22a) 19, 31, 50 | 22b) 6, 13, 33 | 22c) 8, 11, 30 |
26) 19 squares, 2n – 1
Section 2.2
16a)
Section 2.3
Section 3.1
4a) P = 33.05 in.
4b) 28.8 cm.
10a) d = 12 ft., r = 6 ft.
10b) d = 5.05 cm, r = 2.53 cm.
28) A = 20 sq.
in. The area of the unshaded region is one-half the
area of the total region.
Section 3.2
38) 1256 sq. ft.
Section 3.3
4a) 180m2
4b)
30) The sum of the areas of the 3 triangles equals the area of the trapezoid:
Multiplying both sides by 2 to get rid of the fractions:
ab + ab + c2 = (a + b)(a + b)
2ab + c2 = a2 + 2ab + b2
Subtracting 2ab from both sides:
c2 = a2 + b2
28c) No
28d) Box A
52) 3.77 gallons
18) True. The converse says: "If an angle
is obtuse, then it measures 117 degrees. False.
26) False. The converse says:
"If two angles are adjacent, then they share a common vertex." True.
Section
4.2
10) Not necessarily congruent (no AAA Congruence
Postulate)
14)
22)
D
24) CBA, ASA Congruence Postulate
26) C, CPCTC (Corresponding Parts of
Congruent Triangles are Congruent)
35) Note that the segments in steps 2 and
3 should have segments signs over them.
Statements | Reasons |
1. ABCD is a rhombus | 1. Given |
2.
AB![]() ![]() | 2. Definition of a rhombus |
3.
BD![]() | 3. Reflexive Property |
4. ![]() ![]() ![]() | 4. SSS Congruence Postulate |
Statements | Reasons |
1. Segments AC and BD divide each other in half | 1. Given |
2.
AE![]() ![]() | 2. Definition of "divides each other in half" |
3. angle
BEC![]() | 3. Vertical
angles are ![]() |
4.
![]() ![]() ![]() | 4. SAS Congruence Postulate |
5. angle DBC![]() | 5. CPCTC |
Statements | Reasons |
1.
![]() ![]() | 1. Given |
2.
AB![]() ![]() | 2. Given |
3. AB+BC = AF + FE | 3. Adding = quantities to both sides of the equation |
4.
AC![]() | 4. Segment Addition |
5. ![]() ![]() ![]() | 5. HL Congruence Theorem |
6. angle ACF![]() | 6. CPCTC |
46) The ropes are the
same length so ADCD . The ropes
are anchored the same distance from the base of the tree so AB
CB
.
Since DBDB , we know
ABD
CBD
by SSS Congruence Postulate. Thus, angle ABD
angle CBD by CPCTC. Since angle ABD and angle CBD are also adjacent and supplementary,
they both measure 90°. Therefore, the tree will be perpendicular to the ground.
Section 4.3
9.Note that the segments in steps 2 and 5 should have segments signs over them.
Statements | Reasons |
1.
angle WVY![]() ![]() ![]() | 1. Given |
2.
VW![]() ![]() | 2. If 2 angles of a triangle are ![]() ![]() |
3.
angle VWY![]() | 3.
Each is 180 degrees minus 2 ![]() |
4. ![]() ![]() ![]() | 4. SAS Congruence Postulate |
5. WX![]() | 5. CPCTC |
Statements | Reasons |
1.
PY & RX are altitudes PX ![]() | 1. Given |
2. ![]() ![]() | 2. Definition of altitude |
3. PR![]() | 3. Reflexive Property |
4. ![]() ![]() ![]() | 4. HL Congruence Theorem |
Statements | Reasons |
1.
BD is an altitude of ![]() BD is the bisector of angle B | 1. Given |
2. angle BDA & angle BDC are right angles | 2. Definition of altitude |
3.
angle BDA ![]() | 3.
All right angles are ![]() |
4.
angle ABD![]() | 4. Definition of bisector |
5. BD ![]() | 5. Reflexive property |
6. ![]() ![]() ![]() |
6. ASA Congruence Postulate |
7. AD![]() | 7. CPCTC |
8. BD is perpendicular to AC | 8. Definition of altitude |
9. BD is the perpendicular bisector of AC | 9. Definition of perpendicular bisector |
Given:
Prove: BD is the perpendicular bisector of AC | ![]() |
Statements | Reasons |
1.
AB![]() BD is a median | 1. Given |
2. AD![]() | 2. Definition of median |
3. BD![]() | 3. Reflexive property |
4. ![]() ![]() ![]() | 4. SSS Congruence Postulate |
5. angle ADB ![]() | 5. CPCTC |
6. angle ADB & angle CDB are right angles | 6. Two ![]() |
7. BD is the perpendicular to AC | 7. Definition of perpendicular |
8. BD is the perpendicular bisector of AC | 8. Definition of perpendicular bisector |
22.
The worker positioned board CD at the midpoint of board AB, so as long as the
distances AC and BC are equal, the boards are perpendicular by Theorem 4.10.
Section 5.1
2) angles 2 and 5, angles 9 and 12
4) angles 4 and 8, angles 6 and 14
12) angle 20
14) angle 4
32) angle 1 = 47°, angle 2 = 47°, angle 3 = 106°, angle 4 =
133°
Section 6.1
48) Width = 16.2 in., height = 21.6 in.
Section 6.2
26)